Optimal. Leaf size=168 \[ \frac{3 i b c \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right )}{2 d^2}-\frac{3 i b c \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right )}{2 d^2}-\frac{3 c^2 x \left (a+b \sinh ^{-1}(c x)\right )}{2 d^2 \left (c^2 x^2+1\right )}-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (c^2 x^2+1\right )}-\frac{3 c \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^2}-\frac{b c}{2 d^2 \sqrt{c^2 x^2+1}}-\frac{b c \tanh ^{-1}\left (\sqrt{c^2 x^2+1}\right )}{d^2} \]
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Rubi [A] time = 0.187181, antiderivative size = 168, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 11, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.458, Rules used = {5747, 5690, 5693, 4180, 2279, 2391, 261, 266, 51, 63, 208} \[ \frac{3 i b c \text{PolyLog}\left (2,-i e^{\sinh ^{-1}(c x)}\right )}{2 d^2}-\frac{3 i b c \text{PolyLog}\left (2,i e^{\sinh ^{-1}(c x)}\right )}{2 d^2}-\frac{3 c^2 x \left (a+b \sinh ^{-1}(c x)\right )}{2 d^2 \left (c^2 x^2+1\right )}-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (c^2 x^2+1\right )}-\frac{3 c \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right ) \left (a+b \sinh ^{-1}(c x)\right )}{d^2}-\frac{b c}{2 d^2 \sqrt{c^2 x^2+1}}-\frac{b c \tanh ^{-1}\left (\sqrt{c^2 x^2+1}\right )}{d^2} \]
Antiderivative was successfully verified.
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Rule 5747
Rule 5690
Rule 5693
Rule 4180
Rule 2279
Rule 2391
Rule 261
Rule 266
Rule 51
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{a+b \sinh ^{-1}(c x)}{x^2 \left (d+c^2 d x^2\right )^2} \, dx &=-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (1+c^2 x^2\right )}-\left (3 c^2\right ) \int \frac{a+b \sinh ^{-1}(c x)}{\left (d+c^2 d x^2\right )^2} \, dx+\frac{(b c) \int \frac{1}{x \left (1+c^2 x^2\right )^{3/2}} \, dx}{d^2}\\ &=-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (1+c^2 x^2\right )}-\frac{3 c^2 x \left (a+b \sinh ^{-1}(c x)\right )}{2 d^2 \left (1+c^2 x^2\right )}+\frac{(b c) \operatorname{Subst}\left (\int \frac{1}{x \left (1+c^2 x\right )^{3/2}} \, dx,x,x^2\right )}{2 d^2}+\frac{\left (3 b c^3\right ) \int \frac{x}{\left (1+c^2 x^2\right )^{3/2}} \, dx}{2 d^2}-\frac{\left (3 c^2\right ) \int \frac{a+b \sinh ^{-1}(c x)}{d+c^2 d x^2} \, dx}{2 d}\\ &=-\frac{b c}{2 d^2 \sqrt{1+c^2 x^2}}-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (1+c^2 x^2\right )}-\frac{3 c^2 x \left (a+b \sinh ^{-1}(c x)\right )}{2 d^2 \left (1+c^2 x^2\right )}-\frac{(3 c) \operatorname{Subst}\left (\int (a+b x) \text{sech}(x) \, dx,x,\sinh ^{-1}(c x)\right )}{2 d^2}+\frac{(b c) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{1+c^2 x}} \, dx,x,x^2\right )}{2 d^2}\\ &=-\frac{b c}{2 d^2 \sqrt{1+c^2 x^2}}-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (1+c^2 x^2\right )}-\frac{3 c^2 x \left (a+b \sinh ^{-1}(c x)\right )}{2 d^2 \left (1+c^2 x^2\right )}-\frac{3 c \left (a+b \sinh ^{-1}(c x)\right ) \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{d^2}+\frac{b \operatorname{Subst}\left (\int \frac{1}{-\frac{1}{c^2}+\frac{x^2}{c^2}} \, dx,x,\sqrt{1+c^2 x^2}\right )}{c d^2}+\frac{(3 i b c) \operatorname{Subst}\left (\int \log \left (1-i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{2 d^2}-\frac{(3 i b c) \operatorname{Subst}\left (\int \log \left (1+i e^x\right ) \, dx,x,\sinh ^{-1}(c x)\right )}{2 d^2}\\ &=-\frac{b c}{2 d^2 \sqrt{1+c^2 x^2}}-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (1+c^2 x^2\right )}-\frac{3 c^2 x \left (a+b \sinh ^{-1}(c x)\right )}{2 d^2 \left (1+c^2 x^2\right )}-\frac{3 c \left (a+b \sinh ^{-1}(c x)\right ) \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{b c \tanh ^{-1}\left (\sqrt{1+c^2 x^2}\right )}{d^2}+\frac{(3 i b c) \operatorname{Subst}\left (\int \frac{\log (1-i x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{2 d^2}-\frac{(3 i b c) \operatorname{Subst}\left (\int \frac{\log (1+i x)}{x} \, dx,x,e^{\sinh ^{-1}(c x)}\right )}{2 d^2}\\ &=-\frac{b c}{2 d^2 \sqrt{1+c^2 x^2}}-\frac{a+b \sinh ^{-1}(c x)}{d^2 x \left (1+c^2 x^2\right )}-\frac{3 c^2 x \left (a+b \sinh ^{-1}(c x)\right )}{2 d^2 \left (1+c^2 x^2\right )}-\frac{3 c \left (a+b \sinh ^{-1}(c x)\right ) \tan ^{-1}\left (e^{\sinh ^{-1}(c x)}\right )}{d^2}-\frac{b c \tanh ^{-1}\left (\sqrt{1+c^2 x^2}\right )}{d^2}+\frac{3 i b c \text{Li}_2\left (-i e^{\sinh ^{-1}(c x)}\right )}{2 d^2}-\frac{3 i b c \text{Li}_2\left (i e^{\sinh ^{-1}(c x)}\right )}{2 d^2}\\ \end{align*}
Mathematica [C] time = 0.59534, size = 253, normalized size = 1.51 \[ -\frac{\frac{b c \text{Hypergeometric2F1}\left (-\frac{1}{2},1,\frac{1}{2},c^2 x^2+1\right )}{\sqrt{c^2 x^2+1}}-3 b \sqrt{-c^2} \text{PolyLog}\left (2,\frac{c e^{\sinh ^{-1}(c x)}}{\sqrt{-c^2}}\right )+3 b \sqrt{-c^2} \text{PolyLog}\left (2,\frac{\sqrt{-c^2} e^{\sinh ^{-1}(c x)}}{c}\right )-\frac{a}{c^2 x^3+x}+3 a c \tan ^{-1}(c x)+\frac{3 a}{x}-\frac{b \sinh ^{-1}(c x)}{c^2 x^3+x}+3 b c \tanh ^{-1}\left (\sqrt{c^2 x^2+1}\right )+3 b \sqrt{-c^2} \sinh ^{-1}(c x) \log \left (\frac{c e^{\sinh ^{-1}(c x)}}{\sqrt{-c^2}}+1\right )-3 b \sqrt{-c^2} \sinh ^{-1}(c x) \log \left (\frac{\sqrt{-c^2} e^{\sinh ^{-1}(c x)}}{c}+1\right )+\frac{3 b \sinh ^{-1}(c x)}{x}}{2 d^2} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.018, size = 267, normalized size = 1.6 \begin{align*} -{\frac{a}{{d}^{2}x}}-{\frac{a{c}^{2}x}{2\,{d}^{2} \left ({c}^{2}{x}^{2}+1 \right ) }}-{\frac{3\,ca\arctan \left ( cx \right ) }{2\,{d}^{2}}}-{\frac{b{\it Arcsinh} \left ( cx \right ) }{{d}^{2}x}}-{\frac{b{\it Arcsinh} \left ( cx \right ){c}^{2}x}{2\,{d}^{2} \left ({c}^{2}{x}^{2}+1 \right ) }}-{\frac{3\,bc{\it Arcsinh} \left ( cx \right ) \arctan \left ( cx \right ) }{2\,{d}^{2}}}-{\frac{3\,bc\arctan \left ( cx \right ) }{2\,{d}^{2}}\ln \left ( 1+{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) }+{\frac{3\,bc\arctan \left ( cx \right ) }{2\,{d}^{2}}\ln \left ( 1-{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) }+{\frac{{\frac{3\,i}{2}}cb}{{d}^{2}}{\it dilog} \left ( 1+{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) }-{\frac{{\frac{3\,i}{2}}cb}{{d}^{2}}{\it dilog} \left ( 1-{i \left ( 1+icx \right ){\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}} \right ) }-{\frac{bc}{2\,{d}^{2}}{\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}}}-{\frac{bc}{{d}^{2}}{\it Artanh} \left ({\frac{1}{\sqrt{{c}^{2}{x}^{2}+1}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{2} \, a{\left (\frac{3 \, c^{2} x^{2} + 2}{c^{2} d^{2} x^{3} + d^{2} x} + \frac{3 \, c \arctan \left (c x\right )}{d^{2}}\right )} + b \int \frac{\log \left (c x + \sqrt{c^{2} x^{2} + 1}\right )}{c^{4} d^{2} x^{6} + 2 \, c^{2} d^{2} x^{4} + d^{2} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \operatorname{arsinh}\left (c x\right ) + a}{c^{4} d^{2} x^{6} + 2 \, c^{2} d^{2} x^{4} + d^{2} x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a}{c^{4} x^{6} + 2 c^{2} x^{4} + x^{2}}\, dx + \int \frac{b \operatorname{asinh}{\left (c x \right )}}{c^{4} x^{6} + 2 c^{2} x^{4} + x^{2}}\, dx}{d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \operatorname{arsinh}\left (c x\right ) + a}{{\left (c^{2} d x^{2} + d\right )}^{2} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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